# Line slope calculator 3x+y=27

**Straight line given by points A[7; 6] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -3x+27

**Canonical form of the line equation:**3x+y-27 = 0

**Parametric form of the line equation:**

x = t+7

y = -3t+6 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 27

**Distance line from the origin:**d

_{0}= 8.5381

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; -3)

**Normal vector: n =**(3; 1)

**Midpoint of the segment AB: M =**[7.5; 4.5]

**Perpendicular Bisector equation:**x-3y+6 = 0

**Vector OA = (7; 6) ; |OA| = 9.2195**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 74**

**Angle ∠ AOB = 20°2'43″ = 0.3499 rad**